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(A) Given: Emitter current, $I_{E} = 6.6 \, mA$. Current amplification factor, $\beta = 59$. We know that the relationship between emitter current $(I

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$0.11 \, mA$

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(A) Given: Emitter current, $I_{E} = 6.6 \, mA$. Current amplification factor, $\beta = 59$. We know that the relationship between emitter current $(I_{E})$, collector current $(I_{C})$, and base current $(I_{B})$ is $I_{E} = I_{C} + I_{B}$. Since $I_{C} = \beta I_{B}$, we can write $I_{E} = \beta I_{B} + I_{B} = I_{B}(\beta + 1)$. Therefore, the base current is $I_{B} = \frac{I_{E}}{\beta + 1}$. Substituting the values: $I_{B} = \frac{6.6 \, mA}{59 + 1} = \frac{6.6 \, mA}{60} = 0.11 \, mA$.

For a $CE$ transistor amplifier, the current amplification factor is $59$ and the emitter current is $6.6 \, mA$. Then the base current is

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