In an $n-p-n$ transistor, the collector current is $28 \,mA$. If $80 \%$ of electrons reach the collector, its base current in $mA$ is

The collector supply voltage is $6 \text{ V}$ and a voltage drop across a resistor of $600 \Omega$ in the collector circuit is $0.6 \text{ V}$,in a circuit of a transistor connected in common emitter mode. If the current gain is $20$,then the base current is: (in $\text{ mA}$)

In a $CE$ transistor, a change of $8.0 \,mA$ in the emitter current produces a change of $7.8 \,mA$ in the collector current. What change in the base current is necessary to produce the same change in the collector current (in $\mu A$)?

In a transistor circuit, when the base current is increased by $50 \mu A$ keeping the collector voltage fixed at $2 \ V$, the collector current increases by $1 \ mA$. The current gain of the transistor is

In a common emitter transistor amplifier, the output resistance is $500 \text{ k}\Omega$ and the current gain $\beta = 50$. If the power gain of the amplifier is $5 \times 10^6$, what is the input resistance (in $\Omega$)?

When $NPN$ transistor is used as an amplifier,