In a CE transistor, a change of 8.0 ,mA in th | vedclass

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Question

(A) The relationship between emitter current, collector current, and base current is given by the equation: $\Delta I_{E} = \Delta I_{C} + \Delta I_{B

Vedclass · Accepted Answer

$200$

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(A) The relationship between emitter current, collector current, and base current is given by the equation: $\Delta I_{E} = \Delta I_{C} + \Delta I_{B}$.Given values are $\Delta I_{E} = 8.0 \,mA$ and $\Delta I_{C} = 7.8 \,mA$.Substituting these values into the equation: $8.0 \,mA = 7.8 \,mA + \Delta I_{B}$.Therefore, $\Delta I_{B} = 8.0 \,mA - 7.8 \,mA = 0.2 \,mA$.Converting to microamperes: $0.2 \,mA = 0.2 	imes 1000 \mu A = 200 \mu A$.

In a $CE$ transistor, a change of $8.0 \,mA$ in the emitter current produces a change of $7.8 \,mA$ in the collector current. What change in the base current is necessary to produce the same change in the collector current (in $\mu A$)?

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