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(B) For the bucket in the shape of a frustum of a cone,the larger radius $r_{1} = 28\,cm$,the smaller radius $r_{2} = 7\,cm$,and the height $h = 45\,c

Vedclass · Accepted Answer

$48.51$

Vedclass · Answer

(B) For the bucket in the shape of a frustum of a cone,the larger radius $r_{1} = 28\,cm$,the smaller radius $r_{2} = 7\,cm$,and the height $h = 45\,cm$.The volume of the frustum of a cone is given by the formula:$V = \frac{1}{3} \pi h (r_{1}^{2} + r_{2}^{2} + r_{1}r_{2})$Substituting the values:$V = \frac{1}{3} 	imes \frac{22}{7} 	imes 45 	imes (28^{2} + 7^{2} + 28 	imes 7)$$V = \frac{22 	imes 15}{7} 	imes (784 + 49 + 196)$$V = \frac{22 	imes 15}{7} 	imes 1029$$V = 22 	imes 15 	imes 147$$V = 48510\,cm^{3}$Since $1000\,cm^{3} = 1\,litre$:$V = \frac{48510}{1000}\,litres = 48.51\,litres$Thus,the bucket can hold $48.51\,litres$ of water.

For a bucket in the shape of a frustum of a cone,the radii are $28\,cm$ and $7\,cm$ and the height is $45\,cm$. How many litres of water can it hold?

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