For a common emitter configuration,if alpha a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a transistor,the current gain parameters are defined as $\beta = \frac{I_C}{I_B}$ and $\alpha = \frac{I_C}{I_E}$.Since $I_E = I_B + I_C$,we can

Vedclass · Accepted Answer

$\alpha = \frac{\beta}{1 - \beta}$

Vedclass · Answer

(B) In a transistor,the current gain parameters are defined as $\beta = \frac{I_C}{I_B}$ and $\alpha = \frac{I_C}{I_E}$.Since $I_E = I_B + I_C$,we can write $\alpha = \frac{I_C}{I_B + I_C}$.Dividing the numerator and denominator by $I_C$,we get $\alpha = \frac{1}{\frac{I_B}{I_C} + 1} = \frac{1}{\frac{1}{\beta} + 1} = \frac{\beta}{1 + \beta}$.From this,we can derive $\frac{1}{\alpha} = \frac{1 + \beta}{\beta} = \frac{1}{\beta} + 1$,which implies $\frac{1}{\beta} = \frac{1}{\alpha} - 1$.Comparing these with the given options,the relation $\alpha = \frac{\beta}{1 - \beta}$ is incorrect.

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relation between $\alpha$ and $\beta$ is

Similar Questions

An oscillator is nothing but an amplifier with

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is

The output characteristics of an $n-p-n$ transistor represent, ($I_C =$ collector current, $V_{CE} =$ potential difference between collector and emitter, $I_B =$ base current, $V_{BB} =$ voltage given to base, $V_{BE} =$ the potential difference between base and emitter)

If collector current is $120\, mA$,base current is $2\, mA$,and resistance gain is $3$,what is the power gain?

Vedclass Test Series

Exam Paper Generator

Online Exam Module