For a given reaction 3A + B to C + D,the rate | vedclass

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(A) For a general reaction $aA + bB 	o cC + dD$,the rate of reaction is given by: Rate $= -\frac{1}{a}\frac{d[A]}{dt} = -\frac{1}{b}\frac{d[B]}{dt} =

Vedclass · Accepted Answer

$-\frac{1}{3}\frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{d[C]}{dt} = \frac{d[D]}{dt}$

Vedclass · Answer

(A) For a general reaction $aA + bB 	o cC + dD$,the rate of reaction is given by: Rate $= -\frac{1}{a}\frac{d[A]}{dt} = -\frac{1}{b}\frac{d[B]}{dt} = \frac{1}{c}\frac{d[C]}{dt} = \frac{1}{d}\frac{d[D]}{dt}$. For the reaction $3A + B 	o C + D$,the stoichiometric coefficients are $a=3$,$b=1$,$c=1$,and $d=1$. Substituting these values,we get: Rate $= -\frac{1}{3}\frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{d[C]}{dt} = \frac{d[D]}{dt}$. Thus,option $A$ is correct.

For a given reaction $3A + B \to C + D$,the rate of reaction can be represented by:

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