For a reaction X + Y rightleftharpoons 2 Z,1. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction is $X + Y \rightleftharpoons 2 Z$. Initial moles: $X = 1.0 \ mol, Y = 1.5 \ mol, Z = 0.5 \ mol$. Volume of vessel = $1 \ L$. At equil

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(C) The reaction is $X + Y \rightleftharpoons 2 Z$. Initial moles: $X = 1.0 \ mol, Y = 1.5 \ mol, Z = 0.5 \ mol$. Volume of vessel = $1 \ L$. At equilibrium,$[Z] = 1.0 \ mol \ L^{-1}$,so moles of $Z = 1.0 \ mol$. Change in moles of $Z = 1.0 - 0.5 = 0.5 \ mol$. According to stoichiometry,for $2 \ mol$ of $Z$ produced,$1 \ mol$ of $X$ and $Y$ are consumed. So,for $0.5 \ mol$ of $Z$ produced,$0.25 \ mol$ of $X$ and $Y$ are consumed. Equilibrium moles: $X = 1.0 - 0.25 = 0.75 \ mol$. $Y = 1.5 - 0.25 = 1.25 \ mol$. $Z = 1.0 \ mol$. $K_{eq} = \frac{[Z]^2}{[X][Y]} = \frac{(1.0)^2}{(0.75)(1.25)} = \frac{1}{0.9375} = \frac{1}{15/16} = \frac{16}{15}$. Given $K_{eq} = \frac{x}{15}$,therefore $x = 16$.

Similar Questions

$5 \, \text{moles}$ of $PCl_5$ are heated in a closed vessel of $5 \, \text{L}$ capacity. At equilibrium,$40\%$ of $PCl_5$ is found to be dissociated. What is the value of $K_c$ (in $, \text{M}$)?

For the equilibrium $N_2O_4(g) \rightleftharpoons 2NO_2(g)$ in a closed vessel at a constant temperature,if the volume of the reaction vessel is halved,which of the following statements is true regarding the equilibrium constant $K_p$ and the degree of dissociation $(\alpha)$?

$2NOBr_{(g)} \rightleftharpoons 2NO_{(g)} + Br_{2_{(g)}}$. If $NOBr$ is $40\%$ dissociated at a certain temperature and a total pressure of $0.30 \text{ atm}$,the $K_p$ for the reaction $2NO_{(g)} + Br_{2_{(g)}} \rightleftharpoons 2NOBr_{(g)}$ is:

For the reaction,$N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$,if dinitrogen tetroxide is $50\%$ dissociated at $60^\circ C$,the standard free energy change at this temperature and $1 \ atm$ pressure is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module