For a transistor,in a common emitter arrangement,the alternating current gain $\beta$ is given by

  • A
    $\beta = \left( \frac{\Delta I_C}{\Delta I_B} \right)_{V_{CE}}$
  • B
    $\beta = \left( \frac{\Delta I_B}{\Delta I_C} \right)_{V_{CE}}$
  • C
    $\beta = \left( \frac{\Delta I_C}{\Delta I_E} \right)_{V_{CE}}$
  • D
    $\beta = \left( \frac{\Delta I_E}{\Delta I_C} \right)_{V_{CE}}$

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In a common emitter transistor amplifier, an input signal of $10 \ mV$ is applied. Due to this signal, the change in base current is $50 \ \mu A$ and the corresponding change in collector current is $5 \ mA$. If the load resistance in the collector-emitter circuit is $5 \ k\Omega$, the change in output voltage will be ..... $V$.

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$A$ common emitter circuit is used as an amplifier with a current gain of $50$. If the input resistance is $1 \ k\Omega$ and the input voltage is $5 \ V$, then the output current is ....... $mA$.

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