For a transistor,$\alpha_{dc}$ and $\beta_{dc}$ are the current ratios,then the value of $\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc} \times \beta_{dc}}$ is:

$A$ $N-P-N$ transistor is connected in common emitter configuration (see figure) in which the collector voltage drop across the load resistance $(800 \; \Omega)$ connected to the collector circuit is $0.8 \; V$. The collector current is .............. $mA$.

The input signal given to a $C.E.$ amplifier having a voltage gain of $126$ is $V_i = 2 \cos \left(12 t + \frac{\pi}{3}\right)$. The corresponding output signal will be

$A$ transistor is operated in common emitter configuration at $V_C = 2 \, V$ such that a change in the base current from $100 \, \mu A$ to $300 \, \mu A$ produces a change in the collector current from $10 \, mA$ to $20 \, mA$. The current gain is

If the resistance $R_1$ is increased (see figure), how will the readings of the ammeter and voltmeter change?

In a $CE$ circuit,the collector of a transistor is kept at a constant voltage $V_C = 1.5 \ V$. When the base current changes from $100 \ \mu A$ to $150 \ \mu A$,the collector current changes from $5 \ mA$ to $10 \ mA$. The current gain $\beta$ for this transistor is: