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(A) In a common emitter configuration,the current gain $\beta$ is defined as the ratio of the change in collector current to the change in base curren

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(A) In a common emitter configuration,the current gain $\beta$ is defined as the ratio of the change in collector current to the change in base current.$\beta = \frac{\Delta I_C}{\Delta I_B}$Given:Change in collector current,$\Delta I_C = 20 \, mA - 10 \, mA = 10 \, mA = 10 	imes 10^{-3} \, A$Change in base current,$\Delta I_B = 300 \, \mu A - 100 \, \mu A = 200 \, \mu A = 200 	imes 10^{-6} \, A$Substituting these values into the formula:$\beta = \frac{10 	imes 10^{-3}}{200 	imes 10^{-6}}$$\beta = \frac{10}{200} 	imes 10^3$$\beta = \frac{1}{20} 	imes 1000 = 50$Therefore,the current gain is $50$.

$A$ transistor is operated in common emitter configuration at $V_C = 2 \, V$ such that a change in the base current from $100 \, \mu A$ to $300 \, \mu A$ produces a change in the collector current from $10 \, mA$ to $20 \, mA$. The current gain is

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