In an $NPN$ transistor,if the doping in the base region is increased,then the collector current:

Assertion: $A$ transistor amplifier in common emitter configuration has a low input impedance.
Reason: The base-to-emitter region is forward-biased.

$A$ transistor is operated in common-emitter configuration at $V_{CE} = 2\, V$ such that a change in the base current from $100\,\mu A$ to $200\,\mu A$ produces a change in the collector current from $5\, mA$ to $10\, mA$. The current gain is

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

According to a graph drawn between the input and output voltages of a transistor connected in common emitter configuration, the region in which the transistor acts as a switch is

An $n-p-n$ transistor with current gain $\beta=100$ in common emitter configuration is shown in the figure. The output voltage of the amplifier will be $.....V$.