An $n-p-n$ transistor with current gain $\beta=100$ in common emitter configuration is shown in the figure. The output voltage of the amplifier will be $.....V$.

$A$ transistor is connected in a common emitter configuration with $R_o = 4 \text{ k}\Omega$,$R_i = 1 \text{ k}\Omega$,$I_C = 1 \text{ mA}$,and $I_b = 20 \text{ }\mu\text{A}$. The voltage gain is:

In a transistor amplifier,the base-emitter junction is forward-biased and the collector-emitter junction is reverse-biased. The current gain is defined as:

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relation between $\alpha$ and $\beta$ is

The input signal given to a $CE$ amplifier having a voltage gain of $150$ is $V_{in} = 2 \cos(15t + \frac{\pi}{3}) \text{ V}$. The corresponding output signal will be:

For a transistor,the parameter $\beta = 99$. The value of the parameter $\alpha$ is