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(A) Given, input signal $V_{i} = 2 \cos(15t + \frac{\pi}{3})$ and voltage gain $A_{v} = 150$.The voltage gain is defined as $A_{v} = \frac{V_{o}}{V_{i

Vedclass · Accepted Answer

$300 \cos(15t + \frac{4\pi}{3}) 	ext{ V}$

Vedclass · Answer

(A) Given, input signal $V_{i} = 2 \cos(15t + \frac{\pi}{3})$ and voltage gain $A_{v} = 150$.The voltage gain is defined as $A_{v} = \frac{V_{o}}{V_{i}}$, so the output signal magnitude is $V_{o} = A_{v} 	imes V_{i}$.A common emitter $(CE)$ amplifier introduces a phase shift of $\pi$ $(180^{\circ})$ between the input and output signals.Therefore, the output signal is $V_{o} = 150 	imes 2 \cos(15t + \frac{\pi}{3} + \pi)$.Simplifying the phase, $\frac{\pi}{3} + \pi = \frac{4\pi}{3}$.Thus, $V_{o} = 300 \cos(15t + \frac{4\pi}{3}) 	ext{ V}$.

The input signal given to a $CE$ amplifier having a voltage gain of $150$ is $V_{in} = 2 \cos(15t + \frac{\pi}{3}) \text{ V}$. The corresponding output signal will be:

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