$A$ transistor is operated in common-emitter configuration at $V_{CE} = 2\, V$ such that a change in the base current from $100\,\mu A$ to $200\,\mu A$ produces a change in the collector current from $5\, mA$ to $10\, mA$. The current gain is

In an $NPN$ transistor, the collector current is $28 \text{ mA}$. If $80\%$ of the electrons emitted by the emitter reach the collector, what is the base current in $\text{mA}$ (in $\text{ mA}$)?

In a common emitter transistor amplifier circuit,the input resistance is $1.8 \text{ k}\Omega$ and the output is obtained across a load resistance of $9 \text{ k}\Omega$. The alternating current gain is $70$. Corresponding to an a.c. input voltage of $6 \text{ mV}$,the output voltage will be: (in $\text{ V}$)

If $ \alpha $-current gain of a transistor is $ 0.98 $,what is the value of $ \beta $-current gain of the transistor?

$A$ transistor is operated in $CE$ configuration at $V_{CC} = 2 \ V$ such that a change in base current from $100 \ \mu A$ to $200 \ \mu A$ produces a change in the collector current from $9 \ mA$ to $16.5 \ mA$. The value of current gain,$\beta$ is .........

The input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.