For a transistor,alpha_{dc} and beta_{dc} are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We know the relationship between the current gain parameters $\alpha_{dc}$ and $\beta_{dc}$ is given by $\beta_{dc} = \frac{\alpha_{dc}}{1 - \alph

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) We know the relationship between the current gain parameters $\alpha_{dc}$ and $\beta_{dc}$ is given by $\beta_{dc} = \frac{\alpha_{dc}}{1 - \alpha_{dc}}$.Rearranging this equation,we get $1 - \alpha_{dc} = \frac{\alpha_{dc}}{\beta_{dc}}$.Now,we need to evaluate the expression $\frac{\beta_{dc} - \alpha_{dc}}{\alpha_{dc} \cdot \beta_{dc}}$.This can be written as $\frac{\beta_{dc}}{\alpha_{dc} \cdot \beta_{dc}} - \frac{\alpha_{dc}}{\alpha_{dc} \cdot \beta_{dc}} = \frac{1}{\alpha_{dc}} - \frac{1}{\beta_{dc}}$.Substituting $\frac{1}{\alpha_{dc}} = \frac{1 + \beta_{dc}}{\beta_{dc}}$ is not necessary here; instead,use $\frac{1}{\alpha_{dc}} - \frac{1}{\beta_{dc}} = \frac{\beta_{dc} - \alpha_{dc}}{\alpha_{dc} \cdot \beta_{dc}}$.From the relation $\beta_{dc} = \frac{\alpha_{dc}}{1 - \alpha_{dc}}$,we have $\frac{1}{\beta_{dc}} = \frac{1 - \alpha_{dc}}{\alpha_{dc}} = \frac{1}{\alpha_{dc}} - 1$.Therefore,$\frac{1}{\alpha_{dc}} - \frac{1}{\beta_{dc}} = 1$.Thus,the value of the expression is $1$.

For a transistor,$\alpha_{dc}$ and $\beta_{dc}$ are the current ratios. Then the value of $\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc} \cdot \beta_{dc}}$ is

Similar Questions

The current gain $\beta$ of a transistor is $50$. The input resistance of the transistor when used in the common emitter mode is $1\,k\Omega$. The peak value of the collector current for an input peak voltage of $0.01\,V$ is ...... $\mu A$.

In a common emitter amplifier, a change of $0.2 \text{ mA}$ in the base current causes a change of $5 \text{ mA}$ in the collector current. If input resistance is $2 \text{ k}\Omega$ and voltage gain is $75$, the load resistance used in the circuit is

In the transistor circuit shown,the base current is $35 \mu A$. The value of the resistor $R_b$ is......$ k \Omega$.

$A$ transistor connected in common emitter mode has a load resistance of $5 \, k\Omega$. If the input peak voltage is $5 \, mV$ and the current gain $(\beta)$ is $50$, find the voltage gain.

In an $npn$ transistor, $10^{10}$ electrons enter the emitter in $10^{-6} \; s$. If $4\%$ of the electrons are lost in the base, the current transfer ratio $(\alpha)$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module