In an $npn$ transistor, $10^{10}$ electrons enter the emitter in $10^{-6} \; s$. If $4\%$ of the electrons are lost in the base, the current transfer ratio $(\alpha)$ will be:

In a common emitter transistor amplifier, the output resistance is $500 \text{ k}\Omega$ and the current gain $\beta = 50$. If the power gain of the amplifier is $5 \times 10^6$, what is the input resistance (in $\Omega$)?

In which section of a transistor is the doping concentration highest to produce a large number of majority charge carriers?

For a $CE$ transistor amplifier, the current amplification factor is $59$ and the emitter current is $6.6 \, mA$. Then the base current is

What is the voltage gain of a common-emitter amplifier with an input resistance of $3 \ \Omega$ and a load resistance of $24 \ \Omega$? (Given $\beta = 6$)

The part of a transistor which is heavily doped to produce a large number of majority carriers is