For a transistor amplifier,the power gain and voltage gain are $7.5$ and $2.5$ respectively. The value of the current gain will be:

In an $n-p-n$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$. If $2\%$ of the electrons are lost in the base,the current amplification factor $\beta$ is:

In a common emitter transistor circuit,the base current is $40 \ \mu A$. Find the value of $V_{BE}$. (in $V$)

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

In a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2 \, k\Omega$ is $2 \, V$. If the base resistance is $1 \, k\Omega$ and the current amplification of the transistor is $100$,the input signal voltage is

What is the voltage gain of a common-emitter amplifier with an input resistance of $3 \ \Omega$ and a load resistance of $24 \ \Omega$? (Given $\beta = 6$)