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(C) Let the inputs be $A$ and $B$, and the output be $Y$.Given conditions:$1$. When $A = 0$ and $B = 0$, $Y = 1$.$2$. When $A = 1$ and $B = 0$, $Y = 0

Vedclass · Accepted Answer

$NOR$

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(C) Let the inputs be $A$ and $B$, and the output be $Y$.Given conditions:$1$. When $A = 0$ and $B = 0$, $Y = 1$.$2$. When $A = 1$ and $B = 0$, $Y = 0$.Checking the truth tables:- For a $NOR$ gate: $0 NOR 0 = 1$ and $1 NOR 0 = 0$. This matches the given conditions.- For a $NAND$ gate: $0 NAND 0 = 1$ and $1 NAND 0 = 1$. This does not match.- For an $OR$ gate: $0 OR 0 = 0$ and $1 OR 0 = 1$. This does not match.- For an $XOR$ gate: $0 XOR 0 = 0$ and $1 XOR 0 = 1$. This does not match.Therefore, the logic gate is a $NOR$ gate.

For a two-input logic gate, when the inputs are $0$ and $0$, the output is $1$. When the inputs are $1$ and $0$, the output is $0$. The type of logic gate is:

Similar Questions

The following diagram performs the logic function of:

The truth table given below represents which logic gate?
$A$ $B$ $Y$
$0$ $0$ $0$
$0$ $1$ $1$
$1$ $0$ $1$
$1$ $1$ $1$

The combination of $NAND$ gates is shown in the figure. It is equivalent to which gate?

The truth table given below is for which gate?
$A: 0, 0, 1, 1$
$B: 0, 1, 0, 1$
$C: 1, 1, 1, 0$

What will be the input of $A$ and $B$ for the Boolean expression $(\overline{A + B}) \cdot (\overline{A \cdot B}) = 1$?

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