For any two complex numbers z_1 and z_2 and a | vedclass

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(B) We use the property $|z|^2 = z \cdot \overline{z}$.$|az_1 - bz_2|^2 + |bz_1 + az_2|^2 = (az_1 - bz_2)(\overline{az_1 - bz_2}) + (bz_1 + az_2)(\ove

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$(a^2 + b^2)(|z_1|^2 + |z_2|^2)$

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(B) We use the property $|z|^2 = z \cdot \overline{z}$.$|az_1 - bz_2|^2 + |bz_1 + az_2|^2 = (az_1 - bz_2)(\overline{az_1 - bz_2}) + (bz_1 + az_2)(\overline{bz_1 + az_2})$$= (az_1 - bz_2)(a\overline{z_1} - b\overline{z_2}) + (bz_1 + az_2)(b\overline{z_1} + a\overline{z_2})$$= (a^2|z_1|^2 - ab z_1\overline{z_2} - ab \overline{z_1}z_2 + b^2|z_2|^2) + (b^2|z_1|^2 + ab z_1\overline{z_2} + ab \overline{z_1}z_2 + a^2|z_2|^2)$$= a^2|z_1|^2 + b^2|z_2|^2 + b^2|z_1|^2 + a^2|z_2|^2$$= (a^2 + b^2)|z_1|^2 + (a^2 + b^2)|z_2|^2$$= (a^2 + b^2)(|z_1|^2 + |z_2|^2)$

For any two complex numbers $z_1$ and $z_2$ and any real numbers $a$ and $b$,what is the value of $|az_1 - bz_2|^2 + |bz_1 + az_2|^2$?

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