For each of the following $A.P.s$,find the $n^{th}$ term: $10.5, 11.7, 12.9, 14.1, \dots$

Can any term of the $A.P.$ $14, 18, 22, \ldots$ be $142$? If yes,which term?

Find the number of terms in the finite $A.P.$ $7, 11, 15, \ldots, 107$.

The $n^{th}$ term of an $A.P.$ is given by $T_n = 3n - 1$. For this $A.P.$,the common difference $d = \ldots$

If the sum of the $3^{\text{rd}}$ and the $8^{\text{th}}$ terms of an $AP$ is $7$ and the sum of the $7^{\text{th}}$ and the $14^{\text{th}}$ terms is $-3,$ find the $10^{\text{th}}$ term.

The $11^{\text{th}}$ term of the $AP: -5, \frac{-5}{2}, 0, \frac{5}{2}, \dots$ is