For silver,Young's modulus is 7.25 times 10^{ | vedclass

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(C) The relationship between Young's modulus $(Y)$,Bulk modulus $(K)$,and Poisson's ratio $(\sigma)$ is given by the formula: $Y = 3K(1 - 2\sigma)$.Re

Vedclass · Accepted Answer

$0.39$

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(C) The relationship between Young's modulus $(Y)$,Bulk modulus $(K)$,and Poisson's ratio $(\sigma)$ is given by the formula: $Y = 3K(1 - 2\sigma)$.Rearranging the formula to solve for $\sigma$:$1 - 2\sigma = \frac{Y}{3K}$$2\sigma = 1 - \frac{Y}{3K}$$\sigma = \frac{3K - Y}{6K}$Substituting the given values $Y = 7.25 	imes 10^{10} \ N/m^2$ and $K = 11 	imes 10^{10} \ N/m^2$:$\sigma = \frac{3(11 	imes 10^{10}) - 7.25 	imes 10^{10}}{6(11 	imes 10^{10})}$$\sigma = \frac{33 	imes 10^{10} - 7.25 	imes 10^{10}}{66 	imes 10^{10}}$$\sigma = \frac{25.75}{66} \approx 0.39$.

For silver,Young's modulus is $7.25 \times 10^{10} \ N/m^2$ and Bulk modulus is $11 \times 10^{10} \ N/m^2$. Its Poisson's ratio will be

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