For the calculation of mode of the following | vedclass

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Question

(A) In the given frequency distribution,the maximum frequency is $8$,which corresponds to the class interval $5-7$.Therefore,the modal class is $5-7$.

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) In the given frequency distribution,the maximum frequency is $8$,which corresponds to the class interval $5-7$.Therefore,the modal class is $5-7$.In the formula for mode,$f_{1}$ is the frequency of the modal class,$f_{0}$ is the frequency of the class preceding the modal class,and $f_{2}$ is the frequency of the class succeeding the modal class.Here,the modal class is $5-7$,so its frequency $f_{1} = 8$.The class preceding the modal class is $3-5$,and its frequency is $f_{0} = 3$.Thus,$f_{0} = 3$.

Class	$1-3$	$3-5$	$5-7$	$7-9$	$9-11$
Frequency	$6$	$3$	$8$	$2$	$1$

Monthly income range (in $Rs.$)	Number of families
Income more than $10000$	$100$
Income more than $13000$	$85$
Income more than $16000$	$69$
Income more than $19000$	$50$
Income more than $22000$	$33$
Income more than $25000$	$15$

Class	$50-70$	$70-90$	$90-110$	$110-130$	$130-150$	$150-170$
Frequency	$10$	$18$	$7$	$6$	$5$	$4$

For the calculation of mode of the following frequency distribution,$f_{0} = \dots \dots \dots \dots \dots$

Class $1-3$ $3-5$ $5-7$ $7-9$ $9-11$

Frequency $6$ $3$ $8$ $2$ $1$

Similar Questions

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$c = \dots$

For some given data,if $M = 62.5$ and $\bar{x} = 64$,then $Z = \ldots$

If $Z+M=34$ and $M+\bar{x}=40,$ then $M=\ldots \ldots \ldots . . .$

Find the mean of the following data by all the three methods:

Class $50-70$ $70-90$ $90-110$ $110-130$ $130-150$ $150-170$

Frequency $10$ $18$ $7$ $6$ $5$ $4$

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For the calculation of mode of the following frequency distribution,$f_{0} = \dots \dots \dots \dots \dots$ Class $1-3$ $3-5$ $5-7$ $7-9$ $9-11$ Frequency $6$ $3$ $8$ $2$ $1$