For the decimal expansion of a rational numbe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) rational number $\frac{p}{q}$ has a terminating decimal expansion if and only if the prime factorization of the denominator $q$ is of the form $2^

Vedclass · Accepted Answer

$N \cup \{0\}$

Vedclass · Answer

(B) rational number $\frac{p}{q}$ has a terminating decimal expansion if and only if the prime factorization of the denominator $q$ is of the form $2^m \cdot 5^n$,where $m$ and $n$ are non-negative integers.Non-negative integers include all natural numbers $(N)$ and zero $(0)$.Therefore,$m, n \in N \cup \{0\}$.

$Q.1.$ $HCF$ of $8$ and $6$	$A. 49$
$Q.2.$ $LCM$ of $(26, 91)$	$B. 182$
	$C. 2$

For the decimal expansion of a rational number $\frac{p}{q}$ to be terminating,if $q = 2^m \cdot 5^n$,then $m, n \in$ . . . . . . ($R$,$N \cup \{0\}$,$Z$)

Similar Questions

Prove that $\sqrt{2}$ is irrational.

If $\frac{x^{3}-1}{p(x)}=\frac{x^{2}+x+1}{x-1}$,then $p(x) = \dots$

If $p$ and $q$ are distinct prime integers,then their Least Common Multiple $(LCM)$ is . . . . . . .

Match the following items:
$Q.1.$ $HCF$ of $8$ and $6$ $A. 49$
$Q.2.$ $LCM$ of $(26, 91)$ $B. 182$
$C. 2$

Is $\sqrt{2}$ a rational number?

Vedclass Test Series

Exam Paper Generator

Online Exam Module