For the first order reaction A rightarrow 2B, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(NONE) For the reaction $A \rightarrow 2B$:At $t=0$,$[A]_0 = 1 \ mol$ and $[B] = 0$.At $t=100 \ min$,let the amount of $A$ reacted be $x$. Then $[A]_t

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(NONE) For the reaction $A \rightarrow 2B$:At $t=0$,$[A]_0 = 1 \ mol$ and $[B] = 0$.At $t=100 \ min$,let the amount of $A$ reacted be $x$. Then $[A]_t = 1-x$ and $[B] = 2x$.Given $2x = 0.2 \ mol$,so $x = 0.1 \ mol$.Thus,$[A]_t = 1 - 0.1 = 0.9 \ mol$.The rate constant $k$ is given by $k = \frac{1}{t} \ln \frac{[A]_0}{[A]_t} = \frac{1}{100} \ln \frac{1}{0.9} = \frac{1}{100} \ln(1.111)$.Using $\ln(1.111) \approx 0.105$,$k \approx 0.00105 \ min^{-1}$.The half-life $t_{1/2} = \frac{\ln 2}{k} = \frac{0.69}{0.00105} \approx 657 \ min$.

For the first order reaction $A \rightarrow 2B$,$1 \ mole$ of reactant $A$ gives $0.2 \ moles$ of $B$ after $100 \ minutes$. The half-life of the reaction is $..... \ min$. [Use: $\ln 2 = 0.69, \ln 10 = 2.3$]

Similar Questions

Among the following statements,the correct statement about the half-life period for a first order reaction is

In a first order reaction,the concentration of the reactant is reduced to $1/8$ of the initial concentration in $75 \ minutes$. The $t_{1/2}$ of the reaction (in minutes) is $(\log 2 = 0.30, \log 3 = 0.47, \log 4 = 0.60)$.

Initial concentration of reactant in a first order reaction is $0.08 \text{ mol dm}^{-3}$. What concentration would remain after $40 \text{ minutes}$? (Given $\frac{[A]_0}{[A]_t} = 5.00$)

For any reaction,if we plot a graph between time $t$ and $\log (a - x)$,a straight line is obtained. The order of reaction is

The half-life of a first-order reaction is $850 \text{ s}$. The initial concentration of the reactant is $[R]_0 = 0.06 \text{ mol dm}^{-3}$. What concentration $[R]$ would remain after $t = 1200 \text{ s}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module