For the following data,the median class is ld | vedclass

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(D) To find the median class,we first calculate the cumulative frequency $(cf)$ for the given data:$1$. Class $0-10$: Frequency $12$,$cf = 12$$2$. Cla

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$20-30$

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(D) To find the median class,we first calculate the cumulative frequency $(cf)$ for the given data:$1$. Class $0-10$: Frequency $12$,$cf = 12$$2$. Class $10-20$: Frequency $18$,$cf = 12 + 18 = 30$$3$. Class $20-30$: Frequency $20$,$cf = 30 + 20 = 50$$4$. Class $30-40$: Frequency $17$,$cf = 50 + 17 = 67$$5$. Class $40-50$: Frequency $13$,$cf = 67 + 13 = 80$The total number of observations $N = 80$.We find $N/2 = 80/2 = 40$.The median class is the class interval whose cumulative frequency is greater than or equal to $N/2 = 40$.Looking at the cumulative frequencies $(12, 30, 50, 67, 80)$,the first value greater than $40$ is $50$.Therefore,the corresponding class interval is $20-30$.

Class	$200-299$	$300-399$	$400-499$	$500-599$	$600-699$	$700-799$	$800-899$
Frequency	$3$	$61$	$118$	$139$	$126$	$151$	$2$

For the following data,the median class is $\ldots \ldots \ldots$

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$

Frequency $12$ $18$ $20$ $17$ $13$

Similar Questions

Find the mean of the following data:

Class $200-299$ $300-399$ $400-499$ $500-599$ $600-699$ $700-799$ $800-899$

Frequency $3$ $61$ $118$ $139$ $126$ $151$ $2$

$\frac{Z-M}{M-\bar{x}}=\ldots \ldots \ldots \ldots$

For some given data,if $Z = 95$ and $\bar{x} = 98,$ then $M = \ldots \ldots \ldots$

If the modal class of a frequency distribution is $70-85,$ then in the formula for mode,$l=$ ..........

Find the mean of the following frequency distribution:

Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$

Frequency $2$ $10$ $40$ $25$ $13$ $10$

(in $.7$)

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Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$
Frequency	$12$	$18$	$20$	$17$	$13$

For the following data,the median class is $\ldots \ldots \ldots$ Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ Frequency $12$ $18$ $20$ $17$ $13$