(C) The reaction is $Fe^{2+}_{(aq)} + S^{2-}_{(aq)} \rightleftharpoons FeS_{(s)}$.Since equal volumes are mixed,the new concentrations are $0.03 \ M \

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(C) The reaction is $Fe^{2+}_{(aq)} + S^{2-}_{(aq)} \rightleftharpoons FeS_{(s)}$.Since equal volumes are mixed,the new concentrations are $0.03 \ M \ Fe^{2+}$ and $0.1 \ M \ S^{2-}$.Given $K_{c} = 1.6 \times 10^{17}$,which is very large,the reaction proceeds almost to completion.Let $y$ be the equilibrium concentration of $Fe^{2+}_{(aq)}$.Initial concentrations: $[Fe^{2+}] = 0.03 \ M$,$[S^{2-}] = 0.1 \ M$.At equilibrium: $[Fe^{2+}] = y$,$[S^{2-}] = 0.1 - 0.03 = 0.07 \ M$.$K_{c} = \frac{1}{[Fe^{2+}][S^{2-}]} = \frac{1}{y \times 0.07} = 1.6 \times 10^{17}$.$y = \frac{1}{1.6 \times 0.07} \times 10^{-17} = \frac{1}{0.112} \times 10^{-17} \approx 8.928 \times 10^{-17} \ M$.Thus,$Y \approx 8.93$.

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Mix Examples- 6-1.Equilibrium (Chemical Equilibrium)

Medium

For the following reaction,the equilibrium constant $K_{c}$ at $298 \ K$ is $1.6 \times 10^{17}$.
$Fe^{2+}_{(aq)} + S^{2-}_{(aq)} \rightleftharpoons FeS_{(s)}$
When equal volumes of $0.06 \ M \ Fe^{2+}_{(aq)}$ and $0.2 \ M \ S^{2-}_{(aq)}$ solutions are mixed,the equilibrium concentration of $Fe^{2+}_{(aq)}$ is found to be $Y \times 10^{-17} \ M$. The value of $Y$ is. . . . .

IIT 2019 All IIT

A
$8.80$
B
$8.85$
C
$8.93$
D
$8.95$

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6-1.Equilibrium (Chemical Equilibrium)

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Mix Examples- 6-1.Equilibrium (Chemical Equilibrium)

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DifficultTS EAMCET 2005

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For the reaction $XCO_{3(s)} \rightleftharpoons XO_{(s)} + CO_{2(g)},$ $K_p = 1.642 \text{ atm}$ at $727^{\circ}C.$ If $4 \text{ moles}$ of $XCO_{3(s)}$ were placed into a $50 \text{ L}$ container and heated to $727^{\circ}C,$ what mole percent of the $XCO_3$ remains unreacted at equilibrium?

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$A$ vessel at $1000 \ K$ contains $CO_2$ with a pressure of $0.5 \ atm$. Some of $CO_2$ is converted into $CO$ on addition of graphite. If total pressure at equilibrium is $0.8 \ atm$,then $K_P$ is : (in $atm$)

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