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(D) The given circuit consists of an $OR$ gate followed by a $NAND$ gate.The output of the $OR$ gate is $Y = A + B$.This output $Y$ is one of the inpu

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$1$,$1$

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(D) The given circuit consists of an $OR$ gate followed by a $NAND$ gate.The output of the $OR$ gate is $Y = A + B$.This output $Y$ is one of the inputs to the $NAND$ gate,and the other input is $C$.The final output $D$ of the $NAND$ gate is $D = \overline{Y \cdot C} = \overline{(A + B) \cdot C}$.Case $1$: $A=0, B=0, C=0$$Y = 0 + 0 = 0$$D = \overline{0 \cdot 0} = \overline{0} = 1$Case $2$: $A=1, B=1, C=0$$Y = 1 + 1 = 1$$D = \overline{1 \cdot 0} = \overline{0} = 1$Thus,the logic states of output $D$ are $1, 1$.

For the given combination of logic gates,the inputs $A, B$ and $C$ are as follows. If $A=B=C=0$ and $A=B=1, C=0$,then the logic states of output $D$ are respectively:

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