For the logic circuit shown,the output wavefo | vedclass

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(D) The given circuit consists of two $NAND$ gates at the input followed by another $NAND$ gate. Let the inputs be $A$ and $B$. The output of the firs

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(D) The given circuit consists of two $NAND$ gates at the input followed by another $NAND$ gate. Let the inputs be $A$ and $B$. The output of the first two $NAND$ gates are $\overline{A}$ and $\overline{B}$ respectively (since they act as $NOT$ gates). The final $NAND$ gate takes $\overline{A}$ and $\overline{B}$ as inputs. The output $Y$ is given by $Y = \overline{\overline{A} \cdot \overline{B}}$. By De Morgan's theorem,$Y = \overline{\overline{A}} + \overline{\overline{B}} = A + B$. Thus,the circuit acts as an $OR$ gate. Analyzing the waveforms: For $t=0$ to $1$: $A=0, B=0 \implies Y = 0+0 = 0$. For $t=1$ to $2$: $A=0, B=1 \implies Y = 0+1 = 1$. For $t=2$ to $3$: $A=1, B=0 \implies Y = 1+0 = 1$. For $t=3$ to $4$: $A=1, B=1 \implies Y = 1+1 = 1$. Thus,the output $Y$ is $0$ from $t=0$ to $1$ and $1$ from $t=1$ to $4$.

For the logic circuit shown,the output waveform at $Y$ is

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