For the reaction,$3A + 2B \to C + D$,the differential rate law can be written as:

  • A
    $-\frac{1}{3} \frac{d[A]}{dt} = \frac{d[C]}{dt} = k[A]^n[B]^m$
  • B
    $-\frac{d[A]}{dt} = \frac{d[C]}{dt} = k[A]^n[B]^m$
  • C
    $+\frac{1}{3} \frac{d[A]}{dt} = -\frac{d[C]}{dt} = k[A]^n[B]^m$
  • D
    $-\frac{1}{3} \frac{d[A]}{dt} = \frac{d[C]}{dt} = k[A]^n[B]^m$

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