For the reaction $N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}$,the correct expression of equilibrium constant $K$ is

  • A
    $K = \frac{[NH_3]^2}{[N_2][H_2]^3}$
  • B
    $K = \frac{[N_2][H_2]^3}{[NH_3]^2}$
  • C
    $K = \frac{2[NH_3]}{[N_2] \times 3[H_2]}$
  • D
    $K = \frac{[N_2] \times 3[H_2]}{2[NH_3]}$

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$N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}; K_1$
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$\frac{1}{2} N_{2(g)} + \frac{3}{2} H_{2(g)} \rightleftharpoons NH_{3(g)}; K_3$
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Consider the following gaseous equilibria with equilibrium constants $K_{1}$ and $K_{2}$ respectively:
$SO_{2(g)} + \frac{1}{2} O_{2(g)} \rightleftharpoons SO_{3(g)}$
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