For three low density gases A, B, C,pressure | vedclass

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Question

(A) For an isochoric process (constant volume),the ideal gas equation is given by $PV = nRT$,which can be rearranged as $P = (\frac{nR}{V})T$.Here,$T$

Vedclass · Accepted Answer

$-273$

Vedclass · Answer

(A) For an isochoric process (constant volume),the ideal gas equation is given by $PV = nRT$,which can be rearranged as $P = (\frac{nR}{V})T$.Here,$T$ is the absolute temperature in Kelvin,which is related to the temperature $t$ in Celsius by $T = t + 273.15$.Substituting this into the equation,we get $P = (\frac{nR}{V})(t + 273.15)$.This represents a straight line equation of the form $y = mx + c$,where the intercept on the temperature axis occurs when pressure $P = 0$.Setting $P = 0$,we get $0 = (\frac{nR}{V})(t + 273.15)$,which implies $t + 273.15 = 0$,or $t = -273.15^{\circ}\,C$.Rounding to the nearest integer,the temperature at point '$K$' is $-273^{\circ}\,C$,which represents absolute zero.

For three low density gases $A, B, C$,pressure versus temperature graphs are plotted while keeping them at constant volume,as shown in the figure. The temperature corresponding to the point '$K$' is $...........\,{}^{\circ}\,C$.

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