The volume of a gas at 21^{circ}C temperature | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The ideal gas equation is $PV = nRT = \frac{m}{M}RT$,where $m$ is the mass and $M$ is the molar mass. Since $V = \frac{m}{\rho}$,we have $P = \fra

Vedclass · Accepted Answer

$1.13$

Vedclass · Answer

(C) The ideal gas equation is $PV = nRT = \frac{m}{M}RT$,where $m$ is the mass and $M$ is the molar mass. Since $V = \frac{m}{ho}$,we have $P = \frac{ho RT}{M}$,which implies $\frac{P}{ho T} = \frac{R}{M} = 	ext{constant}$. Therefore,$\frac{P_1}{ho_1 T_1} = \frac{P_2}{ho_2 T_2}$. Given: At state $1$: $T_1 = 21^{\circ}C = 294.15 \,K$,$P_1 = 768 \,mm \,Hg$,$V_1 = 1 \,L$. At state $2$ $(NTP)$: $T_2 = 273.15 \,K$,$P_2 = 760 \,mm \,Hg$,$ho_2 = 1.2 \,g/L$. Using the relation $ho_1 = ho_2 	imes \frac{P_1}{P_2} 	imes \frac{T_2}{T_1}$: $ho_1 = 1.2 	imes \frac{768}{760} 	imes \frac{273.15}{294.15} \approx 1.13 \,g/L$. Since $V_1 = 1 \,L$,the mass $m = ho_1 	imes V_1 = 1.13 \,g/L 	imes 1 \,L = 1.13 \,g$.

The volume of a gas at $21^{\circ}C$ temperature and $768 \,mm$ pressure is $1 \,L$. If the density of the gas is $1.2 \,g/L$ at $NTP$,then its mass will be ..... $g$.

Similar Questions

In the figure,the volume of container $X$ is twice the volume of container $Y$. Both contain an ideal gas. The temperature of $X$ is $200 \, K$ and the temperature of $Y$ is $400 \, K$. If the mass of the gas in $X$ is $m$,what will be the mass of the gas in $Y$?

$A$ pressure $P-$absolute temperature $T$ diagram was obtained when a given mass of gas was heated. During the heating process from state $1$ to state $2$,the volume:

The graph of pressure $P$ and volume $V$ of $1 \text{ mole}$ of an ideal gas at constant temperature is:

An ideal gas has pressure $P$,volume $V$ and absolute temperature $T$. If $m$ is the mass of each molecule and $K$ is the Boltzmann constant,then the density of the gas is:

Pressure of an ideal gas,contained in a closed vessel,is increased by $0.4 \%$ when heated by $1^{\circ} C$. Its initial temperature must be

Vedclass Test Series

Exam Paper Generator

Online Exam Module