For what value of a are the lines x = 3,y = 4 | vedclass

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(A) The given lines are $L_1: x - 3 = 0$,$L_2: y - 4 = 0$,and $L_3: 4x - 3y + a = 0$.Since the lines are concurrent,they must intersect at a single po

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(A) The given lines are $L_1: x - 3 = 0$,$L_2: y - 4 = 0$,and $L_3: 4x - 3y + a = 0$.Since the lines are concurrent,they must intersect at a single point.First,find the intersection point of $L_1$ and $L_2$ by solving $x = 3$ and $y = 4$.The point of intersection is $(3, 4)$.Since the lines are concurrent,this point $(3, 4)$ must satisfy the equation of the third line $L_3: 4x - 3y + a = 0$.Substituting $x = 3$ and $y = 4$ into the equation:$4(3) - 3(4) + a = 0$$12 - 12 + a = 0$$a = 0$.

For what value of $a$ are the lines $x = 3$,$y = 4$,and $4x - 3y + a = 0$ concurrent?

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