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(A) The magnification $m$ of an astronomical telescope is given by the formula $m = -\frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective

Vedclass · Accepted Answer

$100 \, cm, 0.3 \, cm$

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(A) The magnification $m$ of an astronomical telescope is given by the formula $m = -\frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.To maximize the magnification $m$,we need to maximize the ratio $\frac{f_o}{f_e}$.This is achieved by choosing the largest available focal length for the objective lens $(f_o = 100 \, cm)$ and the smallest available focal length for the eyepiece $(f_e = 0.3 \, cm)$.Therefore,the lenses with focal lengths $100 \, cm$ and $0.3 \, cm$ should be chosen.

Four convergent lenses have focal lengths $100 \, cm, 10 \, cm, 4 \, cm$ and $0.3 \, cm$. For a telescope with maximum possible magnification,we choose the lenses of focal length

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