For a telescope,the focal length of the objec | vedclass

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(B) Given:Focal length of objective lens,$f_o = 15\, cm = 150\, mm$.Focal length of eyepiece,$f_e = 10\, mm = 1\, cm$.Tube length,$L = 16\, cm$.For a

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$15$

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(B) Given:Focal length of objective lens,$f_o = 15\, cm = 150\, mm$.Focal length of eyepiece,$f_e = 10\, mm = 1\, cm$.Tube length,$L = 16\, cm$.For a telescope in normal adjustment,the tube length is $L = f_o + f_e = 15\, cm + 1\, cm = 16\, cm$.Since the given tube length matches the sum of the focal lengths,the telescope is in normal adjustment.The magnification $m$ for a telescope in normal adjustment is given by:$m = \frac{f_o}{f_e}$Substituting the values:$m = \frac{15\, cm}{1\, cm} = 15$.Thus,the magnification is $15$.

For a telescope,the focal length of the objective lens is $15\, cm$ and the focal length of the eyepiece is $10\, mm$. If the tube length is $16\, cm$,find the magnification.

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