Four identical cells of EMF E and internal re | vedclass

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(D) From the figure,all four cells are connected in series in the same polarity (the positive terminal of one is connected to the negative terminal of

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Zero

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(D) From the figure,all four cells are connected in series in the same polarity (the positive terminal of one is connected to the negative terminal of the next).Total $EMF$ of the circuit,$E_{eq} = E + E + E + E = 4E$.Total internal resistance of the circuit,$r_{eq} = r + r + r + r = 4r$.The current $I$ flowing through the circuit is given by $I = \frac{E_{eq}}{r_{eq}} = \frac{4E}{4r} = \frac{E}{r}$.The terminal voltage $V$ across any one cell is given by the formula $V = E - Ir$,where $E$ is the $EMF$ of the cell and $r$ is its internal resistance.Substituting the value of $I$,we get $V = E - (\frac{E}{r}) 	imes r = E - E = 0$.Therefore,the terminal voltage across any one cell is Zero.

Four identical cells of $EMF$ $E$ and internal resistance $r$ are connected as shown in the figure. Find the terminal voltage across any one cell.

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