In the following circuit, the current through $6 \Omega$ resistor is

  • A
    $\frac{1}{5} \,A$
  • B
    $\frac{2}{5} \,A$
  • C
    $\frac{1}{4} \,A$
  • D
    $\frac{3}{4} \,A$

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$A$ cell of emf $10 \text{ V}$ and internal resistance $3 \Omega$ is connected in parallel with another cell of emf $7 \text{ V}$ and internal resistance $\frac{3}{5} \Omega$,such that their positive terminals are joined together and their negative terminals are joined together. Their combined positive terminal is joined with the negative terminal,and their combined negative terminal is joined with the positive terminal of a third cell of emf $20 \text{ V}$ with internal resistance $2 \Omega$. The combination can be replaced by a battery of emf $E$ and internal resistance $r$. The values of $E$ and $r$ are respectively:

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