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(B) Total number of cards in a pack $= 52$.Number of kings in a pack $= 4$.Number of queens in a pack $= 4$.Since the events of drawing a king and dra

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$\frac{2}{13}$

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(B) Total number of cards in a pack $= 52$.Number of kings in a pack $= 4$.Number of queens in a pack $= 4$.Since the events of drawing a king and drawing a queen are mutually exclusive,the probability of drawing either a king or a queen is the sum of their individual probabilities.Probability of drawing a king $P(K) = \frac{4}{52} = \frac{1}{13}$.Probability of drawing a queen $P(Q) = \frac{4}{52} = \frac{1}{13}$.Probability of drawing a king or a queen $P(K \cup Q) = P(K) + P(Q) = \frac{1}{13} + \frac{1}{13} = \frac{2}{13}$.

From a pack of $52$ cards,one card is drawn at random. The probability that it is either a king or a queen is:

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