From an external point P,two tangents,PA and | vedclass

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(B) Given that $PA$ and $PB$ are tangents from an external point $P$ to a circle with centre $O$.We know that the lengths of tangents drawn from an ex

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$20$

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(B) Given that $PA$ and $PB$ are tangents from an external point $P$ to a circle with centre $O$.We know that the lengths of tangents drawn from an external point to a circle are equal,so $PA = PB = 10 \, cm$.The perimeter of $	riangle PCD = PC + CD + PD$.Since $CD$ is a tangent at point $E$,it can be written as $CD = CE + ED$.Also,$CE = CA$ and $ED = DB$ (tangents from points $C$ and $D$ respectively).Substituting these into the perimeter formula:Perimeter of $	riangle PCD = PC + (CE + ED) + PD = PC + CA + DB + PD$.Since $PC + CA = PA$ and $PD + DB = PB$,we get:Perimeter of $	riangle PCD = PA + PB = 10 + 10 = 20 \, cm$.

From an external point $P$,two tangents,$PA$ and $PB$ are drawn to a circle with centre $O$. At one point $E$ on the circle,a tangent is drawn which intersects $PA$ and $PB$ at $C$ and $D$,respectively. If $PA = 10 \, cm$,find the perimeter of the triangle $PCD$ (in $cm$).

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