From the given list,the number of compounds w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the oxidation state of Sulphur $(S)$ in each compound:$1$. $SO_3$: $x + 3(-2) = 0 \implies x = +6$$2$. $H_2SO_3$: $2(+1) + x + 3(-2) = 0 \

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) To find the oxidation state of Sulphur $(S)$ in each compound:$1$. $SO_3$: $x + 3(-2) = 0 \implies x = +6$$2$. $H_2SO_3$: $2(+1) + x + 3(-2) = 0 \implies x = +4$$3$. $SOCl_2$: $x + (-2) + 2(-1) = 0 \implies x = +4$$4$. $SF_4$: $x + 4(-1) = 0 \implies x = +4$$5$. $BaSO_4$: $(+2) + x + 4(-2) = 0 \implies x = +6$$6$. $H_2S_2O_7$: $2(+1) + 2x + 7(-2) = 0 \implies 2x = +12 \implies x = +6$The compounds with $+4$ oxidation state are $H_2SO_3, SOCl_2$,and $SF_4$.Therefore,the total number of such compounds is $3$.

From the given list,the number of compounds with $+4$ oxidation state of Sulphur is $ . . . . . . $.
$SO_3, H_2SO_3, SOCl_2, SF_4, BaSO_4, H_2S_2O_7$

Similar Questions

Sulphur has the highest oxidation state in

The oxidation state of sulfur in the anions $SO_3^{2-}$,$S_2O_4^{2-}$,and $S_2O_6^{2-}$ increases in the order:

Oxidation number of $As$ atoms in $H_3AsO_4$ is

What are the oxidation states of both the chlorine atoms in bleaching powder $(CaOCl_2)$?

Carbon is present in the highest oxidation number in

Vedclass Test Series

Exam Paper Generator

Online Exam Module

From the given list,the number of compounds with $+4$ oxidation state of Sulphur is $ . . . . . . $.$SO_3, H_2SO_3, SOCl_2, SF_4, BaSO_4, H_2S_2O_7$