Geometrical isomerism is shown by

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(A) Geometrical isomerism is shown by compounds that have restricted rotation around a double bond and where each carbon atom of the double bond is at

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$2-$butene

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(A) Geometrical isomerism is shown by compounds that have restricted rotation around a double bond and where each carbon atom of the double bond is attached to two different groups.In $2-$butene $(CH_3-CH=CH-CH_3)$,the carbon atoms of the double bond are each bonded to a hydrogen atom $(H)$ and a methyl group $(CH_3)$.Thus,it exists as cis-$2-$butene and trans-$2-$butene,which are geometrical isomers.

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Geometrical isomerism is shown by

Similar Questions

Which of the following does not show geometrical isomerism?

How many geometrical isomers are possible for $1,2$-dimethylcyclohexane?

Determine the correct configuration ($E$ or $Z$) for the following compound:$HN=CH-C(CH_3-NH)=C(CH_2-NH_2)-C \equiv N$

Explain geometric isomerism with an example.

Which of the following does not show geometrical isomerism?

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Determine the correct configuration ($E$ or $Z$) for the following compound:
$HN=CH-C(CH_3-NH)=C(CH_2-NH_2)-C \equiv N$