Which of the following does not show geometri | vedclass

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(B) Geometrical isomerism in cyclic compounds requires that at least two carbons in the ring have different groups attached to them.In structure $(1)$

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$2$

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(B) Geometrical isomerism in cyclic compounds requires that at least two carbons in the ring have different groups attached to them.In structure $(1)$,the $1,2$-dichlorocyclopropane has two different groups on each of the two carbons,allowing for cis and trans forms.In structure $(2)$,the $1,1$-dichlorocyclopropane has two identical $Cl$ atoms on the same carbon atom,which prevents the existence of geometrical isomers.In structure $(3)$,the $1,2$-dibromo-$1,2$-dichlorocyclobutane has different groups on the carbons,allowing for geometrical isomerism.In structure $(4)$,the $1,2,3$-trimethylcyclohexane has different groups on the carbons,allowing for geometrical isomerism.Therefore,structure $(2)$ does not show geometrical isomerism.

Which of the following does not show geometrical isomerism?

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