Provide the $MO$ diagram and explain why the $Ne_{2}$ molecule does not exist.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $Ne_{2}$ $(Z=10)$: $1s^{2} 2s^{2} 2p^{6}$.
Electron configuration in $MO$ for $Ne_{2}$:
$KK(\sigma 2s)^{2} (\sigma^{*} 2s)^{2} (\sigma 2p_{z})^{2} (\pi 2p_{x})^{2} (\pi 2p_{y})^{2} (\pi^{*} 2p_{x})^{2} (\pi^{*} 2p_{y})^{2} (\sigma^{*} 2p_{z})^{2}$
Bond order $= \frac{1}{2} (N_{b} - N_{a}) = \frac{1}{2} (10 - 10) = 0$
Since the bond order is $0$,the molecule is unstable and does not exist. The energy level diagram for $Ne_{2}$ is shown below:

Explore More

Similar Questions

The bond order of which of the following two species is the same?

Among the following,the paramagnetic compound is

When $O_{2}$ is converted into $O_{2}^{+}$,what happens to its paramagnetic character and bond order?

Which one of the following potential energy $(P.E.)$ graphs is not correctly matched?

Difficult
View Solution

During the change of $O_{2}$ to $O_{2}^{-}$,the incoming electron goes to the orbital:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo