Show the heterolytic and homolytic cleavage of $H_3C-Br$.

(N/A) Heterolytic cleavage:
$H_3C-Br \rightarrow H_3C^+ + :Br^-$
In this process,the shared pair of electrons remains with the more electronegative atom $(Br)$,resulting in the formation of a carbocation $(H_3C^+)$ and a bromide ion $(:Br^-)$.
Homolytic cleavage:
$H_3C-Br \rightarrow H_3C^\bullet + ^\bullet Br$
In this process,each atom takes one electron from the shared pair,resulting in the formation of free radicals ($H_3C^\bullet$ and $^\bullet Br$).