Given,HF + H_2O rightleftharpoons H_3O^{+} + | vedclass

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(C) For the dissociation of a weak acid $HF$: $HF + H_2O \rightleftharpoons H_3O^{+} + F^{-}$,$K_a = \frac{[H_3O^{+}][F^{-}]}{[HF]}$ For the hydrolysi

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$K_a 	imes K_b = K_w$

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(C) For the dissociation of a weak acid $HF$: $HF + H_2O ightleftharpoons H_3O^{+} + F^{-}$,$K_a = \frac{[H_3O^{+}][F^{-}]}{[HF]}$ For the hydrolysis of its conjugate base $F^{-}$: $F^{-} + H_2O ightleftharpoons HF + OH^{-}$,$K_b = \frac{[HF][OH^{-}]}{[F^{-}]}$ Multiplying $K_a$ and $K_b$: $K_a 	imes K_b = \frac{[H_3O^{+}][F^{-}]}{[HF]} 	imes \frac{[HF][OH^{-}]}{[F^{-}]} = [H_3O^{+}][OH^{-}] = K_w$ Therefore,the correct relation is $K_a 	imes K_b = K_w$.

Given,$HF + H_2O \rightleftharpoons H_3O^{+} + F^{-}; K_a$
$F^{-} + H_2O \rightleftharpoons HF + OH^{-}; K_b$
Which relation is correct?

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Given,$HF + H_2O \rightleftharpoons H_3O^{+} + F^{-}; K_a$$F^{-} + H_2O \rightleftharpoons HF + OH^{-}; K_b$Which relation is correct?