Given below are two statements for the follow | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Compound $'X'$ $(C_3H_6Cl_2)$ reacts with excess $NaNH_2$ to form propyne $(CH_3-C \equiv CH)$ as compound $'Y'$. $2$. Hydration of propyne $

Vedclass · Accepted Answer

Both Statement $I$ and Statement $II$ are true

Vedclass · Answer

(B) $1$. Compound $'X'$ $(C_3H_6Cl_2)$ reacts with excess $NaNH_2$ to form propyne $(CH_3-C \equiv CH)$ as compound $'Y'$. $2$. Hydration of propyne $(Y)$ with $dil. H_2SO_4/Hg^{2+}$ gives acetone $(CH_3-CO-CH_3)$ as compound $'Z'$. Acetone contains a methyl ketone group and gives a yellow precipitate of iodoform $(CHI_3)$ with $NaOI$. Thus, Statement $I$ is true. $3$. Cyclic trimerization of propyne $(Y)$ using a red hot iron tube gives $1,3,5$-trimethylbenzene (mesitylene) as compound $'Q'$ $(C_9H_{12})$. $4$. In $1,3,5$-trimethylbenzene, there are $3$ aromatic $H$ atoms (on the ring) and $9$ aliphatic $H$ atoms (in the three methyl groups). The ratio of aromatic to aliphatic $H$ atoms is $3:9 = 1:3$. Thus, Statement $II$ is true.

Similar Questions

Which series of reactions will achieve the following transformation?

If the mixture of the following four aromatic compounds is oxidized by a strong oxidizing agent,what is the product?

$A$ isomerises to $B$ on addition of traces of acid $H_2SO_4$. Compound $(B)$ is

Which one of the following is the intermediate in the preparation of a ketone by hydration of an alkyne in the presence of sulfuric acid and mercury $(II)$ sulphate?

$CH_3-C(ONa)=CH_2$ $\xrightarrow{HC\equiv CH}$ $\xrightarrow{H^{+}}$ $\xrightarrow[Pd-BaSO_4]{H_2}$ $\xrightarrow[\Delta]{Al_2O_3}$
End product of the reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module