If the mixture of the following four aromatic compounds is oxidized by a strong oxidizing agent,what is the product?

Answer the following questions:
$(i)$ Give hybridization of Carbon atoms in the following compound: $CH_3-CH=CH-CH_2-C\equiv CH$
$(ii)$ Give the number of $\sigma$ and $\pi$ bonds in the above compound.
$(iii)$ Give the $IUPAC$ name of the above compound.
$(iv)$ Draw the geometrical isomers of the above compound.
$(v)$ Why are $cis$ and $trans$ isomers not possible in alkynes?
$(vi)$ Which bond possesses more bond length between $C=C$ and $C\equiv C$?

Consider the following reactions:
$(a)$ $CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH(Br)-CH_3$
$(b)$ $CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2Br$
$(c)$ $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$
Which of these reactions proceed via a free radical mechanism?

Match List-$I$ with List-$II$ and then select the correct answer from the codes given below the lists.

List-$I$	List-$II$
$A.$ Butane $\to$ Isobutane	$(a).$ Cracking
$B.$ Butane $\to$ Lower hydrocarbons	$(b).$ Isomerisation
$C.$ $n-$Heptane $\to$ Toluene	$(c).$ Reed reaction
$D.$ Propane $\to CH_3CH_2CH_2SO_2Cl$	$(d).$ Aromatization

Which of the following compounds gives a positive Baeyer's test but does not form a white precipitate with ammoniacal silver nitrate solution?

Predict the product of the following reaction: $CH_2=CH-CH_2-CH_2-COOH \xrightarrow{Br_2, NaHCO_3} \text{Product}$