Given electrode potentials:
$Fe^{3+} + e^- \to Fe^{2+}$; $E^o = 0.771 \, V$
$I_2 + 2e^- \to 2I^-$; $E^o = 0.536 \, V$
$E^o_{\text{cell}}$ for the cell reaction
$2Fe^{3+} + 2I^- \to 2Fe^{2+} + I_2$ is:

  • A
    $0.771 - 0.536 = 0.235 \, V$
  • B
    $0.536 - 0.771 = -0.235 \, V$
  • C
    $2 \times 0.771 - 0.536 = 1.006 \, V$
  • D
    $0.771 + 0.536 = 1.307 \, V$

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