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(C) Let $p(x) = ax^3 + bx^2 + cx + d$ be the cubic polynomial.Let the zeroes of the polynomial be $\alpha, \beta,$ and $\gamma$.Given that one of the

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$\frac{c}{a}$

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(C) Let $p(x) = ax^3 + bx^2 + cx + d$ be the cubic polynomial.Let the zeroes of the polynomial be $\alpha, \beta,$ and $\gamma$.Given that one of the zeroes is zero,let $\alpha = 0$.According to the relationship between zeroes and coefficients of a cubic polynomial,the sum of the product of zeroes taken two at a time is given by $\alpha\beta + \beta\gamma + \gamma\alpha = \frac{c}{a}$.Substituting $\alpha = 0$ into the equation:$(0)\beta + \beta\gamma + \gamma(0) = \frac{c}{a}$$0 + \beta\gamma + 0 = \frac{c}{a}$$\beta\gamma = \frac{c}{a}$Thus,the product of the other two zeroes is $\frac{c}{a}$.

Given that one of the zeroes of the cubic polynomial $ax^3 + bx^2 + cx + d$ is zero,the product of the other two zeroes is

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