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Hemoglobin contains $0.34 \%$ of iron by mass. The number of $Fe$ atoms in $3.3 \ g$ of hemoglobin is. (Given : Atomic mass of $Fe$ is $56 \ u, N_A = 6.022 \times 10^{23} \ mol^{-1}$)
- A$1.21 \times 10^{5}$
- B$12.0 \times 10^{16}$
- C$1.21 \times 10^{20}$
- D$3.4 \times 10^{22}$
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